a197a2d3eb
Removed directories for no longer supported architectures.
131 lines
4.1 KiB
NASM
131 lines
4.1 KiB
NASM
dnl Intel Pentium-4 mpn_submul_1 -- Multiply a limb vector with a limb and
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dnl subtract the result from a second limb vector.
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dnl Copyright 2001, 2002 Free Software Foundation, Inc.
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dnl
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dnl This file is part of the GNU MP Library.
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dnl
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dnl The GNU MP Library is free software; you can redistribute it and/or
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dnl modify it under the terms of the GNU Lesser General Public License as
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dnl published by the Free Software Foundation; either version 2.1 of the
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dnl License, or (at your option) any later version.
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dnl
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dnl The GNU MP Library is distributed in the hope that it will be useful,
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dnl but WITHOUT ANY WARRANTY; without even the implied warranty of
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dnl MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
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dnl Lesser General Public License for more details.
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dnl
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dnl You should have received a copy of the GNU Lesser General Public
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dnl License along with the GNU MP Library; see the file COPYING.LIB. If
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dnl not, write to the Free Software Foundation, Inc., 51 Franklin Street,
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dnl Fifth Floor, Boston, MA 02110-1301, USA.
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include(`../config.m4')
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C P4: 7 cycles/limb, unstable timing, at least on early Pentium4 silicon
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C (stepping 10).
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C mp_limb_t mpn_submul_1 (mp_ptr dst, mp_srcptr src, mp_size_t size,
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C mp_limb_t mult);
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C mp_limb_t mpn_submul_1c (mp_ptr dst, mp_srcptr src, mp_size_t size,
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C mp_limb_t mult, mp_limb_t carry);
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C
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C This code is not particularly good at 7 c/l. The dependent chain is only
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C 4 c/l and there's only 4 MMX unit instructions, so it's not clear why that
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C speed isn't achieved.
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C
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C The arrangements made here to get a two instruction dependent chain are
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C slightly subtle. In the loop the carry (or borrow rather) is a negative
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C so that a paddq can be used to give a low limb ready to store, and a high
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C limb ready to become the new carry after a psrlq.
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C
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C If the carry was a simple twos complement negative then the psrlq shift
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C would need to bring in 0 bits or 1 bits according to whether the high was
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C zero or non-zero, since a non-zero value would represent a negative
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C needing sign extension. That wouldn't be particularly easy to arrange and
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C certainly would add an instruction to the dependent chain, so instead an
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C offset is applied so that the high limb will be 0xFFFFFFFF+c. With c in
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C the range -0xFFFFFFFF to 0, the value 0xFFFFFFFF+c is in the range 0 to
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C 0xFFFFFFFF and is therefore always positive and can always have 0 bits
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C shifted in, which is what psrlq does.
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C
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C The extra 0xFFFFFFFF must be subtracted before c is used, but that can be
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C done off the dependent chain. The total adjustment then is to add
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C 0xFFFFFFFF00000000 to offset the new carry, and subtract
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C 0x00000000FFFFFFFF to remove the offset from the current carry, for a net
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C add of 0xFFFFFFFE00000001. In the code this is applied to the destination
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C limb when fetched.
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C
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C It's also possible to view the 0xFFFFFFFF adjustment as a ones-complement
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C negative, which is how it's undone for the return value, but that doesn't
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C seem as clear.
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defframe(PARAM_CARRY, 20)
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defframe(PARAM_MULTIPLIER,16)
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defframe(PARAM_SIZE, 12)
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defframe(PARAM_SRC, 8)
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defframe(PARAM_DST, 4)
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TEXT
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ALIGN(16)
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PROLOGUE(mpn_submul_1c)
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deflit(`FRAME',0)
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movd PARAM_CARRY, %mm1
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jmp L(start_1c)
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EPILOGUE()
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PROLOGUE(mpn_submul_1)
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deflit(`FRAME',0)
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pxor %mm1, %mm1 C initial borrow
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L(start_1c):
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movl PARAM_SRC, %eax
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pcmpeqd %mm0, %mm0
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movd PARAM_MULTIPLIER, %mm7
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pcmpeqd %mm6, %mm6
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movl PARAM_DST, %edx
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psrlq $32, %mm0 C 0x00000000FFFFFFFF
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movl PARAM_SIZE, %ecx
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psllq $32, %mm6 C 0xFFFFFFFF00000000
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psubq %mm0, %mm6 C 0xFFFFFFFE00000001
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psubq %mm1, %mm0 C 0xFFFFFFFF - borrow
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C eax src, incrementing
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C ebx
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C ecx loop counter, decrementing
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C edx dst, incrementing
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C
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C mm0 0xFFFFFFFF - borrow
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C mm6 0xFFFFFFFE00000001
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C mm7 multiplier
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L(loop):
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movd (%eax), %mm1 C src
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leal 4(%eax), %eax
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movd (%edx), %mm2 C dst
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paddq %mm6, %mm2 C add 0xFFFFFFFE00000001
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pmuludq %mm7, %mm1
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psubq %mm1, %mm2 C prod
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paddq %mm2, %mm0 C borrow
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subl $1, %ecx
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movd %mm0, (%edx) C result
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psrlq $32, %mm0
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leal 4(%edx), %edx
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jnz L(loop)
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movd %mm0, %eax
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notl %eax
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emms
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ret
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EPILOGUE()
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