mpir/mpn/x86/pentium4/sse2/submul_1.asm
2008-04-17 21:03:07 +00:00

131 lines
4.1 KiB
NASM

dnl Intel Pentium-4 mpn_submul_1 -- Multiply a limb vector with a limb and
dnl subtract the result from a second limb vector.
dnl Copyright 2001, 2002 Free Software Foundation, Inc.
dnl
dnl This file is part of the GNU MP Library.
dnl
dnl The GNU MP Library is free software; you can redistribute it and/or
dnl modify it under the terms of the GNU Lesser General Public License as
dnl published by the Free Software Foundation; either version 2.1 of the
dnl License, or (at your option) any later version.
dnl
dnl The GNU MP Library is distributed in the hope that it will be useful,
dnl but WITHOUT ANY WARRANTY; without even the implied warranty of
dnl MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
dnl Lesser General Public License for more details.
dnl
dnl You should have received a copy of the GNU Lesser General Public
dnl License along with the GNU MP Library; see the file COPYING.LIB. If
dnl not, write to the Free Software Foundation, Inc., 51 Franklin Street,
dnl Fifth Floor, Boston, MA 02110-1301, USA.
include(`../config.m4')
C P4: 7 cycles/limb, unstable timing, at least on early Pentium4 silicon
C (stepping 10).
C mp_limb_t mpn_submul_1 (mp_ptr dst, mp_srcptr src, mp_size_t size,
C mp_limb_t mult);
C mp_limb_t mpn_submul_1c (mp_ptr dst, mp_srcptr src, mp_size_t size,
C mp_limb_t mult, mp_limb_t carry);
C
C This code is not particularly good at 7 c/l. The dependent chain is only
C 4 c/l and there's only 4 MMX unit instructions, so it's not clear why that
C speed isn't achieved.
C
C The arrangements made here to get a two instruction dependent chain are
C slightly subtle. In the loop the carry (or borrow rather) is a negative
C so that a paddq can be used to give a low limb ready to store, and a high
C limb ready to become the new carry after a psrlq.
C
C If the carry was a simple twos complement negative then the psrlq shift
C would need to bring in 0 bits or 1 bits according to whether the high was
C zero or non-zero, since a non-zero value would represent a negative
C needing sign extension. That wouldn't be particularly easy to arrange and
C certainly would add an instruction to the dependent chain, so instead an
C offset is applied so that the high limb will be 0xFFFFFFFF+c. With c in
C the range -0xFFFFFFFF to 0, the value 0xFFFFFFFF+c is in the range 0 to
C 0xFFFFFFFF and is therefore always positive and can always have 0 bits
C shifted in, which is what psrlq does.
C
C The extra 0xFFFFFFFF must be subtracted before c is used, but that can be
C done off the dependent chain. The total adjustment then is to add
C 0xFFFFFFFF00000000 to offset the new carry, and subtract
C 0x00000000FFFFFFFF to remove the offset from the current carry, for a net
C add of 0xFFFFFFFE00000001. In the code this is applied to the destination
C limb when fetched.
C
C It's also possible to view the 0xFFFFFFFF adjustment as a ones-complement
C negative, which is how it's undone for the return value, but that doesn't
C seem as clear.
defframe(PARAM_CARRY, 20)
defframe(PARAM_MULTIPLIER,16)
defframe(PARAM_SIZE, 12)
defframe(PARAM_SRC, 8)
defframe(PARAM_DST, 4)
TEXT
ALIGN(16)
PROLOGUE(mpn_submul_1c)
deflit(`FRAME',0)
movd PARAM_CARRY, %mm1
jmp L(start_1c)
EPILOGUE()
PROLOGUE(mpn_submul_1)
deflit(`FRAME',0)
pxor %mm1, %mm1 C initial borrow
L(start_1c):
movl PARAM_SRC, %eax
pcmpeqd %mm0, %mm0
movd PARAM_MULTIPLIER, %mm7
pcmpeqd %mm6, %mm6
movl PARAM_DST, %edx
psrlq $32, %mm0 C 0x00000000FFFFFFFF
movl PARAM_SIZE, %ecx
psllq $32, %mm6 C 0xFFFFFFFF00000000
psubq %mm0, %mm6 C 0xFFFFFFFE00000001
psubq %mm1, %mm0 C 0xFFFFFFFF - borrow
C eax src, incrementing
C ebx
C ecx loop counter, decrementing
C edx dst, incrementing
C
C mm0 0xFFFFFFFF - borrow
C mm6 0xFFFFFFFE00000001
C mm7 multiplier
L(loop):
movd (%eax), %mm1 C src
leal 4(%eax), %eax
movd (%edx), %mm2 C dst
paddq %mm6, %mm2 C add 0xFFFFFFFE00000001
pmuludq %mm7, %mm1
psubq %mm1, %mm2 C prod
paddq %mm2, %mm0 C borrow
subl $1, %ecx
movd %mm0, (%edx) C result
psrlq $32, %mm0
leal 4(%edx), %edx
jnz L(loop)
movd %mm0, %eax
notl %eax
emms
ret
EPILOGUE()